If `y=1/(1+x^(a-b)+x^(c-b))+1/(1+x^(b-c)+x^(a-c))+1/(1+x^(b-a)+x^(c-a)),` then (dy)/(dx) is equal to (a)`1` (b) `(a+b+c)^(x+b+c-1)` `0` (d) none of these

Explanation

To find \(\frac{dy}{dx}\) for the given function

\[ y = \frac{1}{1 + x^{a-b} + x^{c-b}} + \frac{1}{1 + x^{b-c} + x^{a-c}} + \frac{1}{1 + x^{b-a} + x^{c-a}}, \]

we will differentiate each term separately using the quotient rule.

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