A `10g` piece of iron `( C =0.45 J//g^(@)C )` at `100^(@)C` is dropped into `25g` of water `( C =4.2 J//g^(@)C)` at `27^(@)C`. Find temperature of the rion and water system at thermal equilibrium .
A
`30^(@)C`
B
`33^(@)C`
C
`40^(@)C`
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
A
Heat lost by iron + Heat gained by water = 0 `10 xx0.45 (T -373)+25xx4.2 xx(T-300)=0` `" "T=303" K or " 30^(@)C`
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