A sample of an ideal gas is expanded `1 m^(3)` to `3 m^(3)` in a reversible process for which `P=KV^(2)` , with `K=6 "bar"//m^(6).` What is work done by the gas (in kJ) ?
A
5200 J
B
15600 kJ
C
52 kJ
D
5267 .6 kJ
Text Solution
Verified by Experts
The correct Answer is:
A
`intdw=-intP.dV` `implies w_("rev")=-int6.V^(2)dV` `=-6[(V_(2)^(3))/(3)-(V_(1)^(3))/(3)]"bar."m^(3),` `w=-5200 " kJ"` so, work done by the gas is 5200 kJ.
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