What is the final temperature of `0.10` mole monoatomic ideal gas that performs `75 cal` of work adiabatically.if the initial temperature is `227 ^(@)C` ( use `R=2 cal //K-mol)`
Calculate the final temperature of a monoatomic ideal gas that is compressed reversible and adiabatically from 16L to 2L at 300 K :
The initial temperature of a two mole monoatomic gas is T. If temperature increases to 3T then work done in the adiabatic process is
An ideal monoatomic gas at 300K expands adiabatically to twice its volume. What is the final temperature?
Calculate the final temperature of the gas, if one mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27^@C and the work done Given (C_V=20J//K)
A monoatomic gas is compressed adiabatically to (8)/(27) of its initial volume if initial temperature is 27^@C , find increase in temperature
When "1" mole of an ideal monoatomic gas is compressed adiabatically the internal energy change involved is "24 cals.The temperature rise is
Five moles of an ideal monoatomic gas with an initial temperature of 150^@C expand and in the process absorb 1500 J of heat and does 2500 J of work. The final temperature of the gas in .^@C is (ideal gas constant R = 8.314 J K^(-1)mol^(-1))
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column
