For the reaction: PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) , if the initial concentration of PCl_(5)=1 mol/ l and x moles/litre of PCl_(5) are consumed at equilibrium, the correct expression of K_(p) if P is total pressure is
The degree of dissociation is 0.4 at 420 K and 1.0 atm for the gaseous reaction PCl_(5)(g)rarrPCl_(3)(g)+Cl_(2)(g) . Assuming ideal behaviour of all gases, calculate the density of equilibrium mixture at 420 K and 1.0 atm. (P = 31, Cl = 35.3)
For the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) the forward reaction at constant temeprature is favoured by
For the reaction PCl_(5)(g) hArr PCl_(3)(g)+Cl__(2)(g) The forward reaction at constant temperature is favoured by
In the reaction PCl_(5)(g) rarr PCl_(3)(g) + Cl_(2)(g) PCl_(5),PCl_(3)"and"Cl_(2) are at equilibrium at 500 K. The concentration of PCl_(3) "and" Cl_(2) is 1.59M. K_(c) = 1.79 .Calculate the concentration of PCl_(5) .
Vapour density of PCl_(3) (g) and Cl_(2) (g) is 100 . Hence , van't Hoff factor for the case : PCl_(5) (g) rarr PCl_(3) (g) + Cl_(2) (g)
For the reaction PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g) the forward reaction at constant temperature is favoured by
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column