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Consider the reaction at 300 K H(2)(g)...

Consider the reaction at 300 K
`H_(2)(g)+Cl_(2)(g)to2HCl(g), DeltaH^(@)=-185kJ`
If 2 mole of `H_(2)` compeletely react with 2 mole of `Cl_(2)` to form `HCl`. What is `DeltaU^(@)` for this reaction ?

A

0

B

`-185 kJ`

C

370 kJ

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
`Deltan_(g)=0 " "therefore" "DeltaH^(@)=DeltaU^(@)`
For 2 mole `DeltaU^(@) =- 370 " kJ"`
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