One mole of an ideal gas undergoes a change of state (2.0) atm, 3.0 L) to (2.0 atm, 7.0 L) with a change in internal energy `(DeltaU) = 30` L-atm. The change in enthalpy `(DeltaH)` of the process in L-atm :
A
22
B
38
C
25
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
B
At constant pressure, `DeltaH=DeltaU+P.DeltaV` `=30 + 2xx4` =38 atm-L
Topper's Solved these Questions
THERMODYNAMICS
NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|6 Videos
THERMODYNAMICS
NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|2 Videos
One mole of a non-ideal gas undergoes a change of state (2.0 atm, 3.01, 95K) to (4.0 atm, 5.01, 245K) with a change in internal energy, DeltaU=30.0L atm. The change in enthalpy DeltaH of the process in L atm is.
One mole of non - ideal gas undergoes a change of state (1.0 atm, 3.0L, 200 K ) to (4.0 atm, 5.0L,250 K) with a change in internal energy (DeltaU)=40 L-atm . The change in enthalpy of the process in L-atm ,
One mole of a non-ideal gas undergoes a change of state (2.0atm,3.0L,95K)rarr(4.0atm,5.0L,245K) With a change in internal energy DeltaE=30L atm. The change in enthalpy (DeltaH) in the process in L -atm is
One mole of non-ideal gas undergoes a change of state ( 2.0 "atm" , 3.0 L , 95 K ) to ( 4.0 "atm" , 5.0 L , 245 K ) with a change in internal energy, DeltaU=30.0 L atm . The change in enthalpy (DeltaH) of the process in L "atm" is
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column
