What is the melting point of benzene if DeltaH_("fusion")=9.95"kJ//mol" and DeltaS_("fusion")35.7J//K - mol ?
For a soild A(s) following sate is giiven is given DeltaH _(fusion)^(@)= 20 kJ"mole"^(-1) DeltaS _(fusion)^(@)= 50 kJ"mole"^(-1)K^(-1) Identify correct option(s) at 1 bar .
For a substance with the value of DeltaH_(vap) and DeltaS_(vap) given below, what is its normal boiling point in .^(@)C (DeltaH_(vap)=59.0 kJ mol^(-1), DeltaS_(vap)=93.65 Jmol^(-1))
The following data is known about the melting of KCl: DeltaH=7.25kJ" "mol^(1) and DeltaS=+0.007JK^(-1)" "mol^(-1) Calcualt eits melting point.
What is the normal boiling point of mercury? Given : DeltaH _(f)^(@)(Hg,l)=0,S^(@)(Hg,l)=77.4 J//K-"mol" DeltaH _(f)^(@)(Hg,g)= 60.8 kJ//"mol", S^(@)(Hg, g)=174.4 J//K-"mol"
Calculate DeltaS for following process : underset("at" 100K)(X(s)) underset("at" 200 K)(rarrX(l)) Given : Melting point of X_(s)=100K,DeltaH_("Fusion")=20kJ//"mol",C_(p.m)(X,l)=10J//"mol".K
The freezing point of 0.02 mol fraction solution of acetic acid (A) in benzene (B) is 277.4K . Acetic acid exists partly as a dimer 2A = A_(2) . Calculate equilibrium constant for the dimerisation. Freezing point of benzene is 278.4K and its heat of fusion DeltaH_(f) is 10.042 kJ mol^(-1) .
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column