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For a perfectly crystalline solid C(p.m....

For a perfectly crystalline solid `C_(p.m.)=aT^(3)`, where ais constant. If `C_(p.m.)` is 0.42.J//K-"mol" at 10K, molar entropy at 10K is:

A

0.42 J/k mol

B

0.14 J/K mol

C

1.12 J/K mol

D

zero

Text Solution

Verified by Experts

The correct Answer is:
C
`0.42=a(10)^(3)impliesa=0.42xx10^(-3)`
`S_(m)=int_(0)^(20)(C_(p,m))/(T)dT`
`=int_(0)^(20)aT^(2)dT=(a)/(3)[20^(3)-0]`
`=1.12 J//K-"mol"`
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