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Suppose that a reaction has DeltaH=-40kJ...

Suppose that a reaction has `DeltaH=-40kJ` and `DeltaS =- 50J//K`. At what temperature range will it change from spontaneous to non-spontaneous?

A

0.8 K to 1 K

B

799 K to 800 K

C

800 K to 801 K

D

799 K to 801 K

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaG_(799)=-40xx1000-799xx(-50)`,
`DeltaG_(799)=-50" J spontaneous"`
`DeltaG_(801)=-40xx1000-801(-50)`
`DeltaG_801=+50 " J non-spontaneous"`
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