Home
Class 11
CHEMISTRY
The entropies of H(2) (g) and H (g) are ...

The entropies of `H_(2)` (g) and H (g) are 130.6 and 114.6 J `mol^(-1)K^(-1)` respectively at 298 K. Using the data given below calculate the bond energy of `H_(2)` (in kJ/mol) :
`H_(2)(g)rarr2H(g),DeltaG^(@)=406.6kJ`

A

377.2

B

436

C

425.5

D

430.5

Text Solution

Verified by Experts

The correct Answer is:
B

`DeltaG=DeltaH-TDeltaS`
`406.6 xx1000=DeltaH-298(2xx114.6 -130.6)`
`DeltaH=406.6 xx1000+298(98.6)`
`DeltaH=436 " kJ mol"^(-1)`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|6 Videos
  • THERMODYNAMICS

    NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|2 Videos
  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|20 Videos

Similar Questions

Explore conceptually related problems

The entropies of H_(2)(g) and H(g) are 130.6 and 114.6J mol^(-1) K^(-1) respectively at 298 K. Using the data given below calculate DeltaH^(@) ( in kJ/ mol) of the reaction given below. H_(2)(g) to 2H(g) , DeltaG^(@) = 406.62 kJ//mol

The entropies of H_(2)(g) and H(g) are 60 " and " 50 J"mole"^(-1)K^(-1) respectively at 300 K. Using the data given below calcualate the bond enthalpy of H_(2)(g) in Kcal "mole"^(-1) . " "H_(2)(g) rarr 2H(g)," "DeltaG^(@)=21.6 KJ "mole"^(-1)

Using the data provided, calculate the multiple bond energy (kJ mol^(-1)) of a C-=C bond in C_(2)H_(2) . That energy is ( take the bond energy of a X-H bond as 350kJ mol^(-1)) . 2C_((s))+H_(2(g))rarr C_(2)H_(2(g)), Delta=225kJ mol^(-1) 2C_((g))rarr 2C_(g)), DeltaH=1410kJ mol^(-1) H_(2(g)) rarr 2H_((g)),DeltaH=330kJ mol^(-1)