An imaginary reaction `X rarr Y` takes place in three steps `X rarr A, DeltaH=-q_(1), " "BrarrA, DeltaH=-q_(2), " "BrarrY, DeltaH=-q_(3)` If Hess's law is applicable, then the heat of the reaction `(X rarr Y)` is :
A hypothetical reaction, A rarr 2B , proceeds via following sequence of steps {:(ArarrC,,DeltaH = q_(1),,,),(CrarrD,,DeltaH = q_(2),,,),((1)/(2)D rarrB,,DeltaH = q_(3),,,):} The heat of reaction is
For the reaction, C+O_(2)rarrCO_(2) , DeltaH=-393 J 2Zn+O_(2) rarr 2ZnO , DeltaH=-412J
Dissociation of water takes place in two steps : H_(2)OrarrH+OH," "DeltaH=+497.8kJ OH rarr H+O," "DeltaH=428.5kJ Water is the bond energy of O-H bond ?
A hypothetical reaction Ato2B , proceeds through following sequence of steps (i) A to C,DeltaH=q (ii) C to D,DeltaH=v (iii) (1)/(2)D to B,DeltaH=x Then, the heat of reaction is
H_(2)(g)+I_(2) (s) rarr 2HI (g), DeltaH=51.9 KJ/mole H_(2)(g)+I_(2)(g) rarr 2 HI (g), DeltaH=-9.2 kJ/mole. the heat of reaction of I_(2)(s) rarr I_(2) (g)
For the reaction 2Cl(g) rarr Cl_(2)(g) , what are the signs of DeltaH and DeltaS ?
Given that , A(s) rarr A(l)DeltaH=x A(l) rarr A(g), DeltaH=y The heat of sublimation of A will be :
Consider the following two reactions: i. Propene +H_(2) rarr Propane, DeltaH_(1) ii. Cyclopropane +H_(2) rarr Propane, DeltaH_(2) Then, DeltaH_(2) - DeltaH_(1) will be:
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column