Use the given standard enthalpies of formation (in kJ/mol) to determine the enthalpy of reaction of the following reaction : `NH_(3)(g)+3F_(2)(g)rarrNF_(3)+3HF(g)` `DeltaH_(f)^(@)(NH_(3),g)=-46.2, " "DeltaH_(f)^(@)(NF_(3),g)=-113.0 ," "DeltaH_(f)^(@)(HF, g)=-269.0`
For the reaction N_(2)(g) + 3H_(2)(g) hArr 2NH_(3)(g), DeltaH=?
Determine the enthalpy of formation of B_(2)H_(6) (g) in kJ/mol of the following reaction : B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g) , Given : Delta_(r )H^(@)=-1941 " kJ"//"mol", " "DeltaH_(f)^(@)(B_(2)O_(3),s)=-1273" kJ"//"mol," DeltaH_(f)^(@)(H_(2)O,g)=-241.8 " kJ"//"mol"
The value of DeltaH-DeltaE for the following reaction at 27^(@)C will be 2NH_(3)(g)toN_(2)(g)+3H_(2)(g)
The standard enthalpy of formation of ammonia gas is Given: N_(2)H_(4) (g) + H_(2) (g) rarr 2NH_(3) (g), Delta H_(r)^(@) = - 40 kJ//mol DeltaH_(f)^(@) [N_(2)H_(4) (g)] = - 120 kJ//mol
Given the following equations and values, determine the enthalpy of reaction at 298 K for reaction: C_(2)H_(4)(g) + 6F_(2)(g) rarr 2CF_(4)(g) + 4HF(g) H_(2)(g) + F_(2)(g) rarr 2HF(g) " "Delta H_(1)^(@) = -537 kJ C(s) + 2F_(2)(g) rarr CF_(4)(g) " "DeltaH_(2)^(@) = -680 kJ 2C(s) + 2H_(2)(g) rarr C_(2)H_(4)(g) " "Delta H_(3)^(@) =52 kJ
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column