C(s)+O_(2)(g)toCO_(2)(g),DeltaH=-94 kcal 2CO(g)+O_(2)to2CO_(2),DeltaH=-135.2 kcal The heat of formation of CO(g) is
If C(s)+O_(2)(g)to CO_(2)(g),DeltaH=rand CO(g)+1/2O_(2)to CO_(2)(g),DeltaH=s then, the heat of formation of CO is
C(s)+(1)/(2)O_(2)(g)to CO(g), Delta H =- 42 kJ/mole CO(g)+(1)/(2)O_(2)(g)to CO_(2)(g) , Delta H =-24 kJ/mole The heat of formation of CO_(2) is
If C(s)+O_(2)(g)rarrCO_(2)(g),DeltaH=X and CO(g)+1//2O_(2)(g)rarrCO_(2)(g),DeltaH=Y , then the heat of formation of CO is
Balance the following equations : CH_(4(g))+O_(2(g))toCO_(2(g))+H_(2)O_((g))
The equations representing the combustion of carbon and carbon monoxide are : C(s) + O_(2)(g) to CO_(2)(g) DeltaH = -394 (kJ)/(mol) CO(s) + 1/2 O_(2)(g) to CO_(2)(g) DeltaH = -284.5 (kJ)/(mol) the heat of formation of 1 mol of CO(g) is :
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column