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The heat of formation of NH(3)(g) is -46...

The heat of formation of `NH_(3)(g)` is `-46 " kJ mol"^(-1)`. The `DeltaH` (in `" kJ mol"^(-1)`) of the reaction, `2NH_(3)(g)rarrN_(2)(g)+3H_(2)(g)` is

A

46

B

`-46`

C

92

D

`-92`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta_(r )H=46xx2=92`
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