Heat of combustion of ethanol at constant pressure and at temperature TK is found to be `-q J" mol"^(-1)`. Hence, heat of combustion (in J `mol^(-1)`) of ethanol at the same temperature and at constant volume will be :
Heat of combustion of ethanol at constant pressure and at temperature T K(=298 K) is found to be -qJ "mol"^(-1) . Hence , heat of combustion (in J "mol"^(-1) ) of ehtanol at the same temperature at constant volume will be:
Heat of combustion of ethanol at constant pressue and at temperature TK(=298K) is found to be -qJmal^(-1) . Hence, heat of combustion (in Jmol^(-1) ) of ethanol at the same temperature at constant volume will be:
The heat of combustion of H_(2)(g) at constant pressure and 300k is -280kJ mol^(-1) . What will be the heat of combustion at constant volume and at 300K ?
The heat of combustion of gaseous methane (CH_(4)) at constant volume is measured in bomb calorimeter at 298K is found to be -885.4kjmol^(-1) . Find the value of enthalpy change at the same temperature.
The combustion of benzene (l) gives CO_(2)(g) and H_(2)O(l) . Given that heat of combustion of benzene at constant volume is –3263.9 kJ mol^(–1) at 25^(@)C , heat of combustion (in kJ mol^(–1) ) of benzene at constant pressure will be (R = 8.314 JK–1 mol–1)
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column