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Calculate the enthalpy for the following...

Calculate the enthalpy for the following reaction using the given bond energies (kJ/mol) :
`(C-H=414, H-O =463, H-Cl = 431, C-Cl=326, C-O =335)`
`CH_(3)-OH(g)+HClrarrCH_(3)-Cl(g)+H_(2)O(g)`

A

`-23` kJ/mol

B

`-42` kJ/mol

C

`-59` kJ/mol

D

`-511` kJ/mol

Text Solution

Verified by Experts

The correct Answer is:
A
`CH_(3)OH(g)+HCl(g)rarrCH_(3)Cl(g)+H_(2)O(g)`
`Delta_(r )H=(B.E.)_(R)-(B.E.)_(P)`
`=3 (C-H)+(C-O)+(O-H)+(H-Cl)`
`-3 (C-H)-(C-Cl)-2(O-H)`
`=335+463 + 431 -326 -2xx463 =-23 " kJ"`
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