Calculate `DeltaS` for 3 mole of a diatomic ideal gas which is heated and compressed from 298 K and 1 bar to 596 K and 4 bar: [Given: `C_(v,m)(gas)=(5)/(2)R,"ln"(2)=0.70,R=2"cal K^(-1)mol^(-1)`]
A
`-14.7"cal K"^(-1)`
B
`+14.7 cal K^(-1)`
C
`-4.9 cal K^(-1)`
D
6.3 cal `K^(-1)`
Text Solution
Verified by Experts
The correct Answer is:
D
`DeltaS=nC_(p,m)"ln"(T_(2))/(T_(1))+nR"in"(P_(1))/(P_(2))` `=3xx(7)/(2)"R ln"((596)/(298))+3" R ln"(1)/(4)` `=-6.3" cal K"^(-1)`
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