Fixed mass of an ideal gas collected in a 24.64 litre sealed rigid vessel at 10 atm is heated from `-73^(@)C` to `27^(@)C` calculate change in gibbs free energy if entropy of gas is a function of temperature as `S=2+10^(-2)T(J//K)(1l atm=0.1kJ)`
A
`1231.5` J
B
`1281.5` J
C
`781.5` J
D
0
Text Solution
Verified by Experts
The correct Answer is:
C
At constant volume, `(P_(1))/(T_(1))=(P_(2))/(T_(2))` `rArr" "P_(2)=1xx(300)/(200)=(3)/(2)` and `V_(1)=24.63L` for single phase `because" "dG=Vdp-"S dT"` `DeltaG=V.DeltaP-int(2+10^(-2)T).dT` `=1231.5-200-(10^(-2)xx50,000)/(2)` = 781.5 J
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