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Fixed mass of an ideal gas collected in a 24.64 litre sealed rigid vessel at 10 atm is heated from `-73^(@)C` to `27^(@)C` calculate change in gibbs free energy if entropy of gas is a function of temperature as `S=2+10^(-2)T(J//K)(1l atm=0.1kJ)`

A

`1231.5` J

B

`1281.5` J

C

`781.5` J

D

0

Text Solution

Verified by Experts

The correct Answer is:
C

At constant volume, `(P_(1))/(T_(1))=(P_(2))/(T_(2))`
`rArr" "P_(2)=1xx(300)/(200)=(3)/(2)`
and `V_(1)=24.63L`
for single phase
`because" "dG=Vdp-"S dT"`
`DeltaG=V.DeltaP-int(2+10^(-2)T).dT`
`=1231.5-200-(10^(-2)xx50,000)/(2)`
= 781.5 J
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