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If enthaopy of hydrogenation of C(6)H(6)...

If enthaopy of hydrogenation of `C_(6)H_(6)(l)` into `C_(6)H_(12)(l)` is `-205kJ//mol` and resonance energy of `C_(6)H_(6)(l)` is `-152kJ//mol` then enthaopy of hydrogenation of

Assume `DeltaH_("vap")` of `C_(6)H_(6)(l),C_(6)H_(8)(l)` all equal :

A

`-535.5kJ//mol`

B

`-238kJ//mol`

C

`-357kJ//mol`

D

`-119` kJ/mol

Text Solution

Verified by Experts

The correct Answer is:
D
Theoretical heat of hydrogenation of benzene = (Actual heat of hydrogenation) + (Resonance energy)

=-205 - 152 =- 357
Enthalpy of hydrogenation of ,
`=(-357)/(3) = - 119` kJ/mol
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