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The first law of thermodynamics for a cl...

The first law of thermodynamics for a closed system is dU = dq + dw, where dw = `dw_(pv)+dw_("non-pv")`. The most common type of `w_("non-pv")` is electrical work. As per IUPAC convention work done on the system is positive.
A system generates 50 J electrical energy, has 150 J of pressure-volume work done on it by the surroundings while releasing 300 J of heat energy. What is the change in the internal energy of the sytem?

A

`-500`

B

`-100`

C

`-300`

D

`-200`

Text Solution

Verified by Experts

The correct Answer is:
D

`DeltaU=q+w`
`DeltaU=-300+(-50+150)=-200`
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