The normal boiling point of a liquid X is 400 K. `DeltaH_("vap")` at normal boiling point is 40 kJ/mol. Select correct statement(s) :

Options

A. `DeltaS_("vaporisation")lt100` J/mol.K at 400 K and 2 atm
B. `DeltaS_("vaporisation")lt10` J/mol.K at 400 K and 1 atm
C. `DeltaG_("vaporisation")lt 0` at 410 K and 1 atm
D. `DeltaU=43.32` kJ/mol.K at 400 K and 1 atm

Answer

A, C

Explanation

`DeltaS_("vap")=(DeltaH)/(B.P.)=(40xx1000)/(400)=100`
`(a) P=2" atm B.P."gt 400K`
`PuarrB.P.uarr" "DeltaS_("vap")lt100`
(c )` DeltaG=DeltaH-TDeltaS`
`=40xx1000-410xx100=-ve`
`DeltaG lt 0`
(d) `DeltaH=DeltaU+Deltan_(g)RT`
`DeltaO=DeltaU+1xx8.31xx10^(-3)xx400`
`DeltaU=36.676 " kJ"//"mol"`