Enthalpy of neutralization of `CH_(3)COOH` by NaOH is less than that of HCl by NaOH. Enthalpy of neutralization of `CH_(3)COOH` is less because of the absorption of heat in the ionization process.
A
If both the statements are TRUE and STATEMENT-2 is the correct explanation of STATEMENT-15
B
If both the statements are TRUE but STATEMENT-2 is NOT the correct explanation of STATEMENT-15
C
If STATEMENT-1 is TRUE and STATEMENT-2 is FALSE
D
If STATEMENT-1 is FALSE and STATEMENT-2 is TRUE
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The correct Answer is:
A
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Enthalpy of neutralization of HCl by NaOH is -55.84 kJ/mol and by NH_(4)OH is 51.34 kJ/mol. The enthalpy of ionization of NH_(4)OH is :
The enthalpy of neutralization of NH_(4)OH and CH_(3)COOH is – 10.5 kcal/mole and enthalpy of neutralization of strong base and CH_(3)COOH is – 12.5 kcal/mole. Calculate the enthalpy of dissociation of NH_(4) OH -
Assertion :- In general, heat of neutralization of CH_(3)COOH by NaOH is less than heat of neutralization of H_(2)SO_(4) by NaOH . Reason :- H_(2)SO_(4) is a di basic acid while CH_(3)COOH is monobasic acid.
Enthalpy of neutralzation is defined as the enthalpy change when 1 mole of acid / / base is completely neutralized by base // acid in dilute solution . For Strong acid and strong base neutralization net chemical change is H^(+) (aq)+OH^(-)(aq)to H_(2)O(l) Delta_(r)H^(@)=-55.84KJ//mol DeltaH_("ionization")^(@) of aqueous solution of strong acid and strong base is zero . when a dilute solution of weak acid or base is neutralized, the enthalpy of neutralization is somewhat less because of the absorption of heat in the ionzation of the because of the absorotion of heat in the ionization of the weak acid or base ,for weak acid /base DeltaH_("neutrlzation")^(@)=DeltaH_("ionization")^(@)+ Delta _(r)H^(@)(H^(+)+OH^(-)to H_(2)O) If enthalpy of neutralization of CH_(3)COOH by NaOH is -49.86KJ // mol then enthalpy of ionization of CH_(3)COOH is:
Enthalpy of neutralization of H_(3)PO_(3) "with " NaOH " is" -106.68 "kJ"//"mol" . If enthalpy of neutralization of HCL with NaOH is -55.84 "kJ"//"mole" , then calculate enthalpy of ionization of H_(3)PO_(3) in to its ions in kJ.
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