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H(2)O^(18) + Na rarr underset("(base)")(...

`H_(2)O^(18) + Na rarr underset("(base)")((A))+(B)`
`CH_(3)-overset(O)overset(||)(C)-O-CH_(2)-CH_(3)+(A) rarr (C)+(D)` alcohol
Product (C) of the reaction is :

A

`CH_(3)-overset(O)overset(||)(C)-underset(18)(O)-H`

B

`CH_(3)-overset(O^(18))overset(||)(C)-O-H`

C

`CH_(3)-overset(O)overset(||)(C)-overset(18)(O^(-))`

D

`CH_(3)-overset(O)overset(||)(C)-O^(Θ)Noverset(o+)(a)`

Text Solution

Verified by Experts

The correct Answer is:
C
(A) `Naoverset(18)OH" "`(B) `H_(2)" "`(c) `CH_(3)-overset(O)overset(||)(C)-overset(18)(O^(ɵ))" "`(D) `CH_(3)-CH_(2)OH`
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