`0.092 g` of a compound with the molecular formula `C_(3)H_(8)O_(3)` on reaction with an excess of `CH_(3)MgI` gives `67.00 mL` of methane at STP. The number of active hydrogen atoms present in a molecule of the compound is :
A
one
B
two
C
three
D
four
Text Solution
Verified by Experts
The correct Answer is:
C
92 g of a compound react with excess of `CH_(3)MgI` to give `x xx 22400 mL` of `CH_(4)` at STP. `1 g` of a compound react with excess of `CH_(3)MgI` to give `(x xx 22400)/(92)` `0.092` of a compound react with excess of `CH_(3)MgI` to give `(x xx 22400)/(92)xx0.092` `(x xx22400xx0.092)/92=67 mL` of `CH_(4)` at `STP` `x=(67xx92)/(22400xx0.092)=(67xx92xx1000)/(22400xx92)=670/224=2.99 ~~3` `x rArr` number of active hydrogen in compound. active `H rArr 3`
Topper's Solved these Questions
ALCOHOL, ETHERS AND EPOXIDES
MS CHOUHAN|Exercise Level 1 (Q.1 To Q.30)|1 Videos
ALCOHOL, ETHERS AND EPOXIDES
MS CHOUHAN|Exercise Level 2|3 Videos
ALCOHOLS AND ETHERS
MS CHOUHAN|Exercise ADDITIONAL OBJECTIVE QUESTIONS (Matrix Match Type ) |3 Videos
Similar Questions
Explore conceptually related problems
Compound having molecular formula C_(3)H_(6)O_(2) is:-
Compound with molecular formula C_3H_6O can show
Compound with molecular formula C_3 H_6 O can show :
The number of saturated compounds with the formula C_(3)H_(6)O is
Compound 'X' with the molecular formula C_(3)H_(8)O on vigronous oxidationy yields an acid C_(3)H_(6)O_(2) .
0.46 g of a compound active hydrogen (molar mass =92 mol^(-1) ) on treatment with excess of CH_(3)MgI releases 336 ml of a gas at STP ( 1 atm pressure). The number of active H atoms per molecule of compound is
A compound with formula C_(6)H_(6)O_(2) gave methane on treatment with excess of MeMgBr, 5.5 g of this compound gave 2.24 litres of methane at STP. How many active hydrogens are present in the compound.
The correct IUPAC name of compound with molecular formula (CH_(3))_(3)C-CH_(3) is
MS CHOUHAN-ALCOHOL, ETHERS AND EPOXIDES-Subjective Problems
