If a particle starts moving along x-axis from origin with initial velocity u=2m/s and acceleration `4m//s^(2)` the relation between displacement and time is given as `x=2t+2t^(2)`. Draw the displacement time graph for `t ul(gt)0`.

Explanation

`x=2(t^(2)+t)=2(t^(2)+t+(1)/(4)-(1)/(4))`
`=2(t+(1)/(2))^(2)-(1)/(4)`
`:. (x+(1)/(4))=2(t+(1)/(2))^(2)`
` :.` Vertex is` (-(1)/(2),-(1)/(2))`
and axis is ` t=-(1)/(2)`
` :. ` Graph is

As graph is to be plotted for ` t ul( gt) 0`
So, graph will be.