Among the following compounds, the one which does not show geometrical isomerism is s

Options

A. `C_(6)H_(56)N=NC_(6)H_(5)`
B. `C_(6)H_(5)CH=CHC_(6)H_(5)`
C. `C_(6)H_(5)-underset(NH_(3))underset(|)( C)=N-OH`
D. `C_(6)H_(5)-underset(C_(6)H_(5))underset(|)( C)=N-CH_(3)`

Answer

To determine which compound among the given options does not show geometrical isomerism, we need to understand the conditions required for geometrical isomerism to occur. Here’s a step-by-step solution:

### Step 1: Understand Geometrical Isomerism
Geometrical isomerism occurs in compounds that have restricted rotation around a double bond (C=C) or a ring structure. For geometrical isomers to exist, there must be two different groups attached to each carbon of the double bond or ring.

**Hint:** Look for double bonds or rings in the compounds to identify potential for geometrical isomerism.

### Step 2: Identify the Compounds
We need to analyze each compound presented in the options. Let's denote them as A, B, C, and D.

**Hint:** Write down the structure of each compound if possible, focusing on the groups attached to the double-bonded carbons.

### Step 3: Analyze Each Compound
- **Compound A:** Contains a nitrogen double bond with two different groups (C6H5 and a lone pair). This can show geometrical isomerism.

- **Compound B:** Has a carbon double bond with different groups (C6H5, OH, and a methyl group). This can also show geometrical isomerism.

- **Compound C:** Contains a carbon double bond with different groups (C6H5 and hydrogen). This can show geometrical isomerism as well.

- **Compound D:** Has a carbon with two identical groups (C6H5) attached to one of the carbons in the double bond. Since there are two identical groups on the same carbon, this compound cannot exhibit geometrical isomerism.

**Hint:** Check for identical groups on the same carbon; if present, the compound will not show geometrical isomerism.

### Step 4: Conclusion
Based on the analysis, **Compound D** is the one that does not show geometrical isomerism because it has two identical groups attached to one carbon atom.

**Final Answer:** The compound that does not show geometrical isomerism is **D**.