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underset((P))(CH(3)Cl)" "underset((Q))(C...

`underset((P))(CH_(3)Cl)" "underset((Q))(CH_(3)CH_(2)Cl)" "underset((R))(CH_(3)CH_(2)CH_(2)Cl)" "underset((S))(CH_(3)-overset(Cl)overset(|)CH-CH_(3))`

A

`PgtQgtSgtR`

B

`PgtQgtRgtS`

C

`SgtRgtQgtP`

D

`SgtQgtRgtP`

Text Solution

Verified by Experts

The correct Answer is:
B
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