If f(x)=|logx|,xgt0,find f^(prime)(1/e) ...

If `f(x)=|logx|,xgt0`,find` f^(prime)(1/e) and f^(prime)(e)`

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`abs x = {(x, x>0),(-x,x<=0):}`
`f(x)``=abs(log x)`=`{(-logx, 0< x <1),(logx,x>=1):}`
`f'(x)={(-1/x, 0< x <1),(1/x,x>=1):}`
For `0<1/e<1`, `f'(1/e)=frac{-1}{1/e}=-e`
For `e>1`, `f'(e)=1/e`

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