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If x^y=y^x ,then find (dy)/(dx)...

If `x^y=y^x` ,then find `(dy)/(dx)`

Text Solution

Verified by Experts

Taking log on both sides `ylogx=xlogy`.
Differentiating both the sides by `uv` rule
`y/x+logx frac{dy}{dx}=x/y frac{dy}{dx}+log y`
`y/x=log y=x/yfrac{dy}{dx}-log y frac{dy}{dx}`
`frac{y-xlogy}{x}=frac{dy}{dx} frac{x-ylog x}{y}` ...
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