{((1)/(3))^(-3)-((1)/(2))^(-3)}-:((1)/(4))^(-3)

{ ((1)/(3))^(-3) - ((1)/(2)) ^(-3) } div ((1)/(4)) ^(-3) = ?

Evaluate { ((1)/(3)) ^(-3) - ((1)/(2)) ^(-3) } div ((1)/(4))^(-3)

{(frac(1)(3))^(-3)-(frac(1)(2))^(-3)} div (frac(1)(4))^(-3)= ?

Simplify ((3(2)/(3))^(2)-(2 (1)/(2)))/((4(3)/(4))^(2)-(3(1)/(3))^(2))+(3(2)/(3)-2(1)/(2))/(4(3)/(4)-3(1)/(3))

(4^(-1)-3^(-1))^(-1)+(2^(-1)-3^(-1))^(-1)=((1)/(4)-(1)/(3))^(-1)+((1)/(2)-(1)/(3))^(-1)

3log 2 +(1)/(4) -(1)/(2)((1)/(4))^(2)+(1)/(3)((1)/(4))^(3)-….. =

3log 2 +(1)/(4) -(1)/(2)((1)/(4))^(2)+(1)/(3)((1)/(4))^(3)-….. =

If ((3(1)/(4) )^(4) -(4( 1)/(3))^(4))/( (3,(1)/(4) )^(2) -(4,(1)/(3))^(2) )= ((13a)/(12))^(2) , find a.

Sum the following geometric series to infinity: (sqrt(2)+1)+1+(sqrt(2)-1)+...oo(1)/(2)+(1)/(3^(3))+(1)/(2^(3))+(1)/(3^(4))+(1)/(2^(5))+(1)/(3^(6))+...oo