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If the derivative of tan^(-1)(a+b x) tak...

If the derivative of `tan^(-1)(a+b x)` takes the value `1` at `x=0,` prove that `1+a^2=bdot`

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Given,`y=tan^(−1)(a+bx)`
⇒`dy/dx​=1/(1+(a+bx)^2)(d/​dx)​(a+bx)`
⇒`dy/dx​=b/(1+(a+bx)^2)`
​ ...
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