T=2 pi sqrt((l)/(g))

Assertion : As the mass of simple pendulum increases, its periodic time increases. Reason : Periodic time of simple pendulum is T= 2pi sqrt((l)/(g)) .

The time period T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to 2% in the value of l.

The period of oscillation of a simple pendulum is given by T=2pi sqrt((l)/(g)) . In finding the value of g, which quantity should be measured most accurately and why?

The time T of oscillation of a simple pendulum of length l is given by T=2pi. sqrt((l)/(g)) . Find the percentage error in T corresponding to (i) on increase of 2% in the value of l. (ii) decrease of 2% in the value of l.