" Devalume: "int((3sin theta-2)cos theta)/(5-cos^(2)theta-4cos theta)d theta

int(2sin2 theta-cos theta)/(6-cos^(2)theta-4sin theta)d theta

int (sin theta cos theta) / (cos ^ (2) theta-cos theta-2) d theta

Find :int((3sin theta-2)cos theta)/(5-cos^(2)theta-4sin theta)dth eta theta

int(2sin theta cos theta)/(sin^(4)theta+cos^(4)theta)d theta

Evaluate the following integrals: int(2sin 2 theta- cos theta)/(6-cos^2 theta- 4 sin theta)d theta

Evaluate : int (2 sin 2 theta- cos theta)/(6 - cos^(2) theta- 4 sin theta) d theta

int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=

Find :int(cos theta)/((4+sin^(2)theta)(5-4cos^(2)theta))d theta

int(d theta)/((sin theta-2cos theta)(2sin theta+cos theta))=

If (sin theta+cos theta)/(sin theta-cos theta)=3 and theta is an acute angle, then the value of (3sin theta+4cos theta)/(8cos theta-3sin theta) is: यदि (sin theta+cos theta)/(sin theta-cos theta)=3 तो (3sin theta+4cos theta)/(8cos theta-3sin theta) का मान ज्ञात करें ।