[" Shore that none of che forlencing is an "],[" identity:- "],[[cos^(2)theta+cos theta=1,0sin^(2)theta+sin theta=2],[sin theta+sin theta=cos^(2)theta]]

cos theta+sin theta=cos2 theta+sin2 theta

sin theta+sin2 theta+sin3 theta=1+cos theta+cos2 theta

(cos^(2)theta(1-cos theta))/(sin^(2)theta(1-sin theta))=(1+sin theta)/(1+cos theta)

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta

Show that none of the following is an identity: (i) cos^(2) theta + cos theta =1 " " (ii) sin^(2) theta + sin theta =2 " " (iii) tan^(2) theta + sin theta = cos^(2) theta

(sin^(2) theta)/(1-cos theta)-(cos^(2) theta)/(1-sin theta)=cos theta-sin theta

If cos2 theta=0 If det[[0,cos theta,sin thetacos theta,sin theta,0sin theta,o,cos theta]]^(2)

If cos theta+cos^(2)theta=1 then sin^(2)theta+2sin^(2)theta+sin^(2)theta=

(sin3 theta-sin theta sin^(2)(2 theta))/(sin theta+sin2 theta cos theta)=cos x then x=

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta