64.(a+2b)^(2)+101(a+2b)+100

Let M=[(a,b,c),(d,e,f),(1,1,1)] and N=(M^(2))/(2) . If (a-b)^(2)+(d-e)^(2)=36, (b-c)^(2)+(e-f)^(2)=64, (a-c)^(2)+(d-f)^(2)=100 , then value of |N| is equal to

The sum 1+3+7+15+31+...to100 terms is 2^(100)-102 b b. 2^(99)-101 c. 2^(101)-102 d. none of these

The sum 1+3+7+15+31+...to100 terms is 2^(100)-102 b b. 2^(99)-101 c. 2^(101)-102 d. none of these

Let S_n=1+q+q^2 +...+q^n and T_n =1+((q+1)/2)+((q+1)/2)^2+...((q+1)/2)^n If alpha T_100=^101C_1 +^101C_2 x S_1 ...+^101C_101 x S_100, then the value of alpha is equal to (A) 2^99 (B) 2^101 (C) 2^100 (D) -2^100

Let S_n=1+q+q^2 +?+q^n and T_n =1+((q+1)/2)+((q+1)/2)^2+?+((q+1)/2)^n If alpha T_100=^101C_1 +^101C_2 xS_1 +^101C_101 xS_100, then the value of alpha is equal to (A) 2^99 (B) 2^101 (C) 2^100 (D) -2^100

The sum 1+3+7+15+31+...to100 terms is a. 2^(100)-102 b. 2^(99)-101 c. 2^(101)-102 d. none of these

The sum 1+3+7+15+31+...to100 terms is a. 2^(100)-102 b. 2^(99)-101 c. 2^(101)-102 d. none of these

In a triangle ABC if a^(2)+b^(2)=101c^(2) then find the value of (cot C)/(cot A+cot B)

The value of 64 a ^(3) + 48 a ^(2) b + 12 a ^(2) b + b ^(3) at a =1 and b =-1 is