If one of the roots of the equation `2x^2-6x+k=0` is `((alpha+5i)/2)`, then the values of a and k are

If one of the roots of the equation 2x^(2)-6x+k=0 is (alpha + 5i)/(2) (where alpha, k in R ) then Statement 1 : the value of alpha is 3 because Statement 2 : the value of k is 17.

If one of the roots of the equation 2x^(2)-6x+k=0 is (alpha + 5i)/(2) (where alpha, k in R ) then Statement 1 : the value of alpha is 3 because Statement 2 : the value of k is 17.

If one root of the equation 2x^(2)-6x+c=0 is (3+5i)/(2), then the real value of c will be

One of the roots of the equation x^2 - 6x + k=0 is x = 2. The other root is:

If one of the root of quadratic equation 6x^(2)-x-k=0 is (2)/(5) , then value of k is___

If one root of the quadratic equation 6x^(2)-x-k=0" is" (2)/(3) , then find the value of k.

If one root of the quadratic equation 6x^(2)-x-k=0" is" (2)/(3) , then find the value of k.

If one root of the equation 2x^2+2x+k=0 is (-1/3) then find teh value of k