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Find the values of `aa n db` so that the function `f(x)={x^2+3x+a ,ifxlt=1b x+2,ifx >1` is differentiable at each `x in Rdot`

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`f(x)=x^2+3x+a, for x<=1`
And`bx+2, for x>1`
The function is everywhere differentiable. So, it is also continuous.
Therefore,
Now,`lim_(x->1)f(x)=lim_(x->1^(+))f(x)`
`lim_(x->1)x^2+3x+a=lim_(x->1)bx+2`
`4+a=b+2`
`a−b=−2 ......(1)`
...
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