Let the intercept made by the line `x/1=y/2=z/3` between the plane x+y+z=3 and the line `[x-1]/2=[y-2]/-1=[z-3]/-1` is `lambda`, then `[4lambda]/sqrt[14]` is

Let the intercept made by the line (x)/(1)=(y)/(2)=(z)/(3) between the plane x+y+z=3 and the line (x-1)/(2)=(y-2)/(-1)=(z-3)/(-1) is lambda then (4 lambda)/(sqrt(14)) is

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane 2x-y+z+3=0 is the line

The length intercepted between the planes x+y+z=3 and x+y+z=2 by the line (x-1)/(2)=(y+1)/(1)=(z-3)/(-1) is:

The image of the line (x-1)/3=(y-3)/1=(z-4)/(-5) in the plane : 2x-y+z+3=0 is the line :

The line (x-1)/2=(y-2)/3=(z-3)/4 meets the plane 2x+3y-z=14 in the point

Find the angle between the plane x+y+z-2=0 and line (x+3)/2=(y-1)/1=(z+1)/4

The angle between the line (x-2)/1=(y+3)/-2=(z+4)/-3 and the plane 2x-3y+z=5 is