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If f(x) ={(|x+2|)/tan^-1(x+2), x != -2 ...

If `f(x) ={(|x+2|)/tan^-1(x+2), x != -2 and 2, x=-2` then `f(x)` is continuous/discontinuous at `x=-2` ?

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Let
`L.H.L=lim_(x->2^(−​))f(x)=lim_(h->0^(+))​f(−2−h)`
=`lim_(h->0^(+))​(∣−2−h+2∣)/(tan^(−1)(−2−h+2) )`
=`lim_(h->0^(+))​ h/(​tan^(−1)(−h))`
=`lim_(h->0^(+)) h/(-​tan^(-1)(h))`
...
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