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Let f(x)=(x+|x|)|x|dot then, for all x ....

Let `f(x)=(x+|x|)|x|dot` then, for all `x` . `f` is continuous (b) `f` is differentiable for some `x` `f'` is continuous (d) `f' '` is continuous

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Consider the given function. `f(x)=(x+|x|)|x|dot`
`f(x)={(x+x)x` for `x>0}`
and `{(x−x)x,​x<0}`
​ `f(x)={2x^2` for `x>0}`
...
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