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A straight line vecr=veca+lambda vecb me...

A straight line `vecr=veca+lambda vecb` meets the plane `vecr. vec n=0 at p.` Then position vector of P is

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State the condition for which the line vecr=veca+lambda vecb is parallel to the plane vecr. vecn=d . Prove that the line vecr=(hati+ hatj)+ lambda (2 hati+ hat j+4 hatk) is parallel to the plane vec r.(-2 hati+ hatk)=5 . Also , find the distance between the line and the plane.

The plane contaning the two straight lines vecr=veca+lamda vecb and vecr=vecb+muveca is (A) [vecr vecas vecb]=0 (B) [vecr veca veca xxvecb]=0 (C) [vecr vecb vecaxxvecb]=0 (D) [vecr veca+vecb vecaxxvecb]=0

The plane contaning the two straight lines vecr=veca+lamda vecb and vecr=vecb+muveca is (A) [vecr veca vecb]=0 (B) [vecr veca veca xxvecb]=0 (C) [vecr vecb vecaxxvecb]=0 (D) [vecr veca+vecb vecaxxvecb]=0