" 16."(3a-1)^(2)-6a+2

factorize (a) (3a-1)^(2)-6a+2

Find the value of the following. 16- (1)/(3)(2pq+6) for p = 2 and q = 3

1-(3)/(16)+(1.4)/(1.2)((3)/(16))^2- (1.4.7)/(1.2.3)((3)/(16))^3 + …..=

Find the equation of the plane passing through the points (3,-1,2) , (5,2,4) ,(-1,-1,6)

Let A={-1,1,-2,2},B={3,4,5,6} and f: A rarr B be the mapping defined by f={(1,6),(-1,4),(2,3),(-2,5)} . Prove that, f is a bijective mapping

Find the distance of the point P(6,5,9) and from the plane through the points (3,-1,2), (5,2,4) and (-1,-1,6).

Factorize each of the following expressions: (2a-b)^(2)-16c^(2)(2)(x+2y)^(2)-4(2x-y)^(2)3a^(5)-48a^(3)(4)a^(4)16b^(4)x^(8)-1(6)64-(a+1)^(2)

{(125)^(-2)xx(16)^(-3/2)}^(-1/6)=

Given that 16^3=4096 , can you compute thesepowers? 1) (1.6)^3 2) (0.16)^3 3) (0.016)^3