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[" 4.The expression "(sin80cos theta-sin...

[" 4.The expression "(sin80cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)" is equals - "],[[" (A) "tan theta," (B) "tan2 theta]]

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Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

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