(6)^(x)2x-3y=4;3y-x=4

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(6) 2x-3y=4 ; 3y-x=4

2x+3y=5 4x-5y=6

2x+3y=8 4x-5y=-6

6x-4y=-12,8x-3y=-2

Find the value of x , y 2x+3y=6 3x-2y=4 .

2x-y+z=6,x+2y+3z=3,3x+y-z=4

4x+3y=4,6x+5y=8

The pole of 2x+3y=0 with respect to x^(2)+y^(2)+6x-4y=0 is

Show that (x^(2)+y^(2))^(4)=(x^(4)-6x^(2)y^(2)+y^(4))^(2)+(4x^(3)y-4xy^(3))^(2)