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If the locus of the foot of the perpendicular drawn from centre upon any tangent to the ellipse `(x^(2))/(40)+(y^(2))/(10)=1` is `(x^(2)+y^(2))^(2)=ax^(2)+by^(2)`, then `(a-b)` is equal to

A

10

B

20

C

25

D

30

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The correct Answer is:
D
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