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The maximum intensity in young's double...

The maximum intensity in young's double-slit experiment is `I_(0)`. Distance between the slit is `d = 5 lambda`, where `lambda` is the wavelength of monochromatic light used in the experiment. What will be the intensity of light in front of one of the slits on a screen at a distance `D = 10 d`?

A

`( I_(0))/( 2)`

B

`(3)/( 4) I_(0)`

C

`(I_(0))/(4)`

D

`I_(0)`

Text Solution

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The correct Answer is:
A
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