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The resistance of wire is 100Omega . If ...

The resistance of wire is `100Omega` . If it is stretched to 4 times its original length , then its new resistance will be

A

`400Omega`

B

`1600Omega`

C

`25Omega`

D

`800Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
Use `R=rhoL/A = rhol^2/V`
Since `RpropL^2`
`R_1/R_2 = L_1^2/L_2^2`
`rArr 100/R_2 = (L^2)/(4L)^2`
`rArr R_2 = 1600Omega`
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