Five capacitors each of capacitance C and breakdown voltage V are connected as shown in the figure. The capacitance and breakdown voltage of the combination (applid across AB) will be

Options

A. `(7C)/(6), V/2`
B. `(7C)/(6),V`
C. `(7C)/(60), (3V)/(2)`
D. `(6C)/(7), V/2`

Answer

C

Explanation

Use voltage divider rule and concept of series and parallel combination of capacitor
`C_(AB) = (Cxx2C)/(C+2C) +(CxxC)/(C+C)`
`=(2C)/(3) +C/2 = (7C)/(6)`
Also , breakdown voltage of combination will be `(3V)/(2)`