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Figure shows the variation of electric f...

Figure shows the variation of electric field intensity E with distance x. The potential difference between the point x = 0 and x= 5m is

A

40V

B

50V

C

30V

D

20V

Text Solution

Verified by Experts

The correct Answer is:
A
Area under electric field - position graph gives potential difference
`DeltaV` = Area under the curve
`=10xx2+1/2xx10xx1+1/2xx10xx1+10xx1`
=20+5+5+10
`DeltaV = 40V`
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